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)/dt = 2/C = 8 V/s Now for the value of dv R(0 )/dt Since v R = v C 10, then dv R(0 )/dt = dv C(0 )/dt 0 = 8 V/s (c) As t approaches infinity, we end up with the equivalent circuit shown in Figure (b) i L(f) = 10(2)/(40 10) = 400 mA v C(f) = –10 = 16 – 10 = 6V v R(f) = = 16 V 40 10 (a) v C 10V v R v. Otherwise, we remove a node from Q 1 and add the corresponding vertex to the current tree. Homework Done Right 18) Prove that the intersection of any collection of subspaces of V is a subspace of V PROOF Let Ω be an indexing set such that Ufi is a subspace of V, for every fi 2 Ω, and let I be the intersection of these subspaces, that is, I = \fi2ΩUfi Since the Ufi’s are all subspaces, 0 2 Ufi for every fi 2 Ω, and so, 0 2 ILet x and y belong to I;.
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E=v/l is which formula of electric field for what kind of conductor Ask questions, doubts, problems and we will help you. S spans V S is linearly independent If S is a linearly dependent set in an ndimensional space V and V=span(S) then by removing some elements of S we can get a basis of V If S is a linearly independent subset of V which is not a basis of V then we can get a basis of V by adding some elements to S Examples 1. This week of events features team building exercises, cultural and social workshops, as well.
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