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Dit is een lijst van afkortingen in het Nederlands Hieronder volgt een lijst van in het Nederlandse taalgebruik voorkomende afkortingen 'In het Nederlandse taalgebruik' hoeft niet te betekenen dat de afkorting naar een Nederlandstalig begrip verwijst Daarom zijn ook afkortingen als ' SOS ' en 'svp' opgenomen. Ma F , W V a U Sa a H a E R b G , L b M a I a c. & * $ ( 1 4 % 4 9 3 8 * & $ 7 $ & , 4 6 ) % 5.

1 Let R = ln(u2 v2 w2), u = x 2y, v = 2x − y, and w = 2xy Use the Chain Rule to find ∂R ∂x and ∂R ∂y when x = y = 1 Solution The Chain Rule gives ∂R ∂x = ∂R ∂u ∂u ∂x ∂R ∂v ∂v ∂x ∂R ∂w ∂w ∂x = 2u u2 v 2w ×1 2v u v 2w ×2 2w u v w2 ×(2y) When x = y = 1, we have u = 3, v = 1, and w = 2, so ∂R ∂x = 6 14 ×1 2 14 ×2 4 14 ×2 = 18 14 = 9 7 ∂R. F a Ă d ݂̌ł ɂ ĉ b ێ a l ĊȒp ɓ ̂ w f 鎖 ł ܂ b. A t h l e t i c D i r e c t o r s s i m p l y n e e d t o c l e ar l y c o m m u n i c at e w i t.

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P = F·v P = vermogen (Js1 of W) F = kracht (N) v = snelheid (ms1) Kinetische energie E k = ½m·v 2 E k = kinetische energie (J) m = massa (kg) v = snelheid (m/s) Zwaarteenergie E z = m·g·h E z = zwaarteenergie (J) m = massa (kg) g = 9,81 m/s 2 (op aarde) h = hoogte (m) Veerenergie E v = ½C·u 2 E v = veerenergie (J) C = veerconstante (N/m) u =uitrekking (m) Chemische energie E ch = r V ·V E ch = r. As ˚respects scalar multiplication As is the inverse of ˚it follows that (rw) = rv= r (w) Thus respects scalar multiplication Hence is linear Lemma 1211 Let V and W be isomorphic vector spaces If one of V and W is nite dimensional then they are both nite. 5 h v s r q v d e loh g h ood v w u x w w x u d r u j d q l d w ly d 6 h u y l lr 6 lv w h p l, q i r u p d w ly lh 7 h oh p d w lf l 3 4 k / dd/s/ / ed 7 lw r or ' h v f u l lr q h 7 ls r $ lr q h 5 lt x d oli lf d lr q.

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Space, W is nonempty, and W is closed under addition and scalar multiplication It follows that every linear combination of vectors of W lies in W Thus, Span(W) W On the other hand, for any w 2W, we have w = 1w, so w 2Span(W) This shows that W Span(W) We have proved that W = Span(W) 1415 Let S 1 and S 2 be subsets of a vector space V. U T c T w _ S U T Z I U ` U W T ¿ c " Z " i U W f T W U l c T s l T Y S T Y W s T i t Y ` Y x U ` T X h U l L g w Y ~ i x T Z U p T T ~ s l T g c w o g `. 5 r p d q r 9 h f f k lh w 5 h v s r q v d e loh g h ood v w u x w w x u d r u j d q l d w ly d 6 h u y l lr , q w h j u d w r 0 x v h lh % le olr w h f k h 3 4 k / dd/s/ / ed 7 lw r or ' h v f u l lr q h 7 ls r $ lr q h.

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