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Here X is a rv having the same distribution as Xj The sum S =åN j=1 Xj where the number in the sum, N is also a random variable and is independent of the Xj’s The following statement now follows from Theorem 1 Theorem 2 (i) ES=E(X)£E(N)=aE(N) (ii) Var(S)=Var(X)£E(N)E(X)2 £Var(N)=s2E(N)a2Var(N) Proof (i) Since ESjN =n=Eån j=1 Xj=å n j=1 EXj=an, we obtain. In cryptography, a classical cipher is a type of cipher that was used historically but for the most part, has fallen into disuse In contrast to modern cryptographic algorithms, most classical ciphers can be practically computed and solved by hand However, they are also usually very simple to break with modern technology. Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history.

Página 2 de 2 INICIO PERIODO LECTIVO • Escuelas INFANTILES, casas de niños y EEII privadas sostenidas con fondos públicos 6 de septiembre 18 • Centros de Educación INFANTIL y PRIMARIA 7 de septiembre 18 • Centros de Educación ESPECIAL 7 de septiembre 18 • Institutos Educación SECUNDARIA 10 de septiembre 18 • BACHILLERATO 10 de septiembre. Search the world's information, including webpages, images, videos and more Google has many special features to help you find exactly what you're looking for. X J L b v ̃n u e B ́A ₩ ȍ ŏ ݂ ܂ B X J L b v ̌ ʂƖ X J L b v ɂ͒ Í p A q X e Ǐ A A R ˑ ǂ̋֒f Ǐ 炰 ʂ ܂ B { A i A ݂Ȃǂ } Ãn u ł.

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